Check 10.4
Write the function safeFind(lst, index) which takes a list and an index. If the index is a valid index return lst[index]; otherwise, return None. You must use try/except in your answer.
def safeFind(lst, index):
pass
def testSafeFind():
print("Testing safeFind()...", end="")
assert(safeFind([1, 2, 3], 2) == 3)
assert(safeFind([1, 2, 3], 5) == None)
assert(safeFind([ ], 0) == None)
print("Done.")
testSafeFind()
import sys
def set_certificate(certificate_div_id, certificate):
document[certificate_div_id].textContent = certificate
def get_student_code(student_code_div_id):
raw_student_code = document[student_code_div_id].textContent
return window.patchCodeToCheckTimeout(raw_student_code, 'check_timeout();');
class captureIO:
def __init__(self):
self.captured = []
def get_output(self):
out = ""
for c in self.captured:
out += str(c)
return out
def write(self, data):
self.captured.append(data)
def flush(self):
pass
def make_certificate(student_code_div_id, certificate_div_id):
certificate = []
student_code = get_student_code(student_code_div_id)
try:
execCapture = captureIO()
sys.stdout = execCapture
sys.stderr = execCapture
exec(student_code)
if not "try:" in student_code or not "except:" in student_code:
set_certificate(certificate_div_id, "No try except")
return
tests = [([0, 4, 4, 1], 0), ([3, 8], 5), ([10, 3, 9], 'foo'), ([0, 5, 2], 5), ([9], 5), ([6, 2, 3, 3], 2), ([1, 4, 2], 1), ([2], 5), ([10], 3), ([0, 5, 10, 1], 2)]
for (lst, idx) in tests:
output = safeFind(lst, idx)
certificate.append((output, type(output)))
set_certificate(certificate_div_id, str(certificate))
except:
set_certificate(certificate_div_id, "error")